We factor by grouping on the denominator on the left now: [tex]\frac{(x+5)(x-1)}{(5x^2-5x)+(-3x+3)} \times \frac{20x-12}{x^2-6x-55}
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\\ \frac{(x+5)(x-1)}{5x(x-1)-3(x-1)} \times \frac{20x-12}{x^2-6x-55}
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\\ \frac{(x+5)(x-1)}{(5x-3)(x-1)} \times \frac{20x-12}{x^2-6x-55}[/tex]
Factor the GCF out of the numerator on the right: [tex]\frac{(x+5)(x-1)}{(5x-3)(x-1)} \times \frac{4(5x-3)}{x^2-6x-55}[/tex]
For the denominator on the right, we want factors of -55 that sum to -6; -11(5) = -55 and -11+5 = -6: [tex]\frac{(x+5)(x-1)}{(5x-3)(x-1)} \times \frac{4(5x-3)}{(x-11)(x+5)}[/tex]
Cancelling everything that is common on the numerators and denominators, we are left with