MATH SOLVE

2 months ago

Q:
# Write the equation of the line perpendicular to -6x+3y=6 that passes through (2,0). Write you answer in slope-intercept formi have downY = mx + b-6x+3y=63y= -6x +6Y = -2x + 2 so far

Accepted Solution

A:

Answer:The answer is: y - 0 = -1/2(x - 2)Step-by-step explanation:Given - an equation in standard form:-6x + 3y = 6Solve for y:Add 6x to both sides:3y = 6 + 6xy = 2 + 2xy = 2x + 2, so the slope is 2.The perpendicular slope is the negative inverse of 2, which is -1/2.Point slope form is:y - y1 = m(x - x1)Substitute in the numbers from the point (2,0) and the slope -1/2:y - 0 = -1/2(x - 2)Taking it to y intercept form:y = -1/2x + 1