The experimental probability that tucker will win a game of chance is 2/5. The experimental probability that lily will win the same game is 5/8. If Tucker and Lily each play 200 games how many more games can lily expect to win that tucker

Answer: Lily can be expected to win 45 more games than Tucker. Step-by-step explanation:The Probability of winning the game for Tucker = 2/5The Probability of winning the game for Lily = 5/8Total number of chances played = 200Now, [tex]\textrm{Probability of winning an Event}  = \frac{\textrm{Total number of wins}}{\textrm{Total number of trials played}}[/tex]⇒Total number of wins  =  P(winning ) x Number of Times it is playedNow, Total number of wins for Tucker =  [tex]\frac{2}{5}  \times 200 = 80[/tex]or, Tucker wins 80 games out of 200 played.And, Total number of wins for Lily =  [tex]\frac{5}{8}  \times 200 = 125[/tex]or,Lily wins 125 games out of 200 played.Hence, Lily is expected to win :125 - 80   =   45 more games than Tucker.